A concave mirror of focal length 20cm is cut into two parts from the middle and the two parts are moved perpendicularly by a distance 1cm from the previous principal axis AB. Find distance between the images formed by the two parts?
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Solution
Let P1Q1= principal axis for the mirror M1&P2Q2= principal axis for the mirror M2 (I1= Image formed by M1,I2= Image formed by M2)
Height of object and image are major with respect to principal axis of respective mirror.
Applying convention, we have, f=−20cm (concave), u=−10cm
and by Mirror formula ⟹1−10+1v=1−20⟹v=20cm
m=−vu=−20−10=2=hiho⟹hi=2cm
(+ve magnification means image and object are on th esame side wuth respect to principal axis.)