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Question

A concave mirror of focal length 20 cm is cut into two parts from the middle and the two parts are moved perpendicularly by a distance 1 cm from the previous principal axis AB. Find distance between the images formed by the two parts?
1023367_aba56234eb1a4a72b986382167e82b3b.png

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Solution

Let P1Q1= principal axis for the mirror M1&P2Q2= principal axis for the mirror M2 (I1= Image formed by M1,I2= Image formed by M2)

Height of object and image are major with respect to principal axis of respective mirror.

Applying convention, we have, f=20cm (concave), u=10cm

and by Mirror formula 110+1v=120v=20cm

m=vu=2010=2=hihohi=2cm

(+ve magnification means image and object are on th esame side wuth respect to principal axis.)

hI1=2cm below the principal axis P1Q1

hi2=2cm above the principal axis P2Q2I1I2=2cm

1445192_1023367_ans_96fa2cf860f04f29b31c8b7715d6ae78.png

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