The mirror produces three times enlarged image.
So, magnification(m) = 3
WE KNOW, magnification of spherical mirrors = m = -v/u
Where v is the distance between image and mirror and u is the distance between object and mirror.
Here, u = -10 cm
=> 3 = -V/-10
=>v = 30
So , the distance between image and mirror = 30 cm
1/v + 1/u = 1/f(mirror formula)
1/30 + 1/-10 = 1/f
1/30 - 1/10 = 1/f
-2/30 = 1/f
-1/15 = 1/f
f = -15 cm
We know radius of curvature = 2f
So, radius of curvature = R = 2*-15 = -30 cm which is the required answer.
SHORTCUT -
Remember the formula, m = f/(f-u)
So, 3 = f/(f-(-10))
3 = f/(f+10)
Cross multiply,
3f + 30 = f
2f = -30
R = -30 cm (R= 2f)