A concave spherical surface of radius of curvature 10cm separates two medium x & y of refractive index 4/3 & 3/2 respectively. If the object is placed along principal axis in medium X then :
A
image is always real
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B
image is real if the object distance is greater than 90 cm
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C
image is always virtual
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D
image is virtual if the object distance is less than 90 cm
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Solution
The correct option is C image is always virtual
Given : R=−10 cm n2=3/2n1=4/3
Let the object is placed at a distance x in front of the spherical surface i.e. u=−x
Using: n2v−n1u=n2−n1R
∴3/2v−4/3−x=3/2−4/3−10
⟹v=−1.5x0.017x+1.33
⟹v<0 i.e. the image formed is always virtual in nature.