A concave spherical surface of radius of curvature 10 cm separates two mediums X and Y of refractive index 43 and 32 respectively. If the object is placed along principal axis in medium X then :
A
Image is always real
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B
Image is real if the object distance is greater than 90 cm
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C
Image is always virtual
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D
Image is virtual if the object distance is less than 90 cm
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Solution
The correct option is C Image is always virtual
Given, R=−10 cm,n2=32,n1=43
Let, the object be placed at a distance x in front of the spherical surface,
i.e., u=−x
Using, n2v−n1u=n2−n1R
From the given data we have, 32v−43−x=32−43−10
⇒v=−1.5x0.017x+1.33
From the above expression we can conclude that v<0, that is image is always virtual in nature.