Dear Student,
Given concentration of solution = 27%
It means solution contains 27g of ammonia per 100 g of solution.
Molar mass of ammonia = 17 g
So, 27 g of ammonia = 27/17 = 1.588 or 1.6 moles
Mass of solution = 100 g
Density of solution = 0.9 g/mL
Volume of solution = Mass/Density = 100/0.9 = 111.11 mL or 0.11 L
So, 1.6 moles of ammonia is present in 0.11 L
Molarity of ammonia solution = Number of moles of ammonia/ Volume of solution
= 1.6/0.11 = 14.55 M
This molarity is not possible in gaseous form and is possible only in solution form. Ammonia dissolves in water to form ammonium hydroxide.
Regards