Question

A concentrated load of 50 kN acts on the surface of ground. The increase in vertical stress directly below the load at a depth of 4 m will be (Value of influence factor is 0.48)

• A. $1.5kN/m^2$
• B. $1.5kN/m^2$
• C. $150kN/m^2$
• D. $0.15kN/m^2$

Answer 1

The correct option is A $1.5kN/m^2$

${\sigma }_z=\frac{Q}{Z^2}{I}_B=\frac{Q}{Z^2}\left(0.48\right)$
$=\frac{50}{4^2}\left(0.48\right)=1.5kN/m^2$