Question

A concentration of $CaC{l}_2$ solution is 0.5 mol/litre; then the moles of chloride ion in 500 mL will be:

• A. 0.5
• B. 0.25
• C. 1
• D. 0.75

Answer 1

The correct option is A 0.5

1 mole of CaCl${}_2$ contains 2 moles of Cl${}^{-}$ ions

moles of Cl${}^{-}$ ions in given solution

=2$\times molarity\times volumes$

=2$\times 0.5\times 500\times {10}^{-3}$

=0.5