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Question

A concentric spherical cavity is cut out from a solid conducting sphere and a charge +Q is placed at the centre of the cavity. The magnitude of net electric field E and net potential V at point A is

A
E=0, V=0
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B
E=0, V=kQ2R
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C
E=kQR2, V=kQ2R
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D
E=0, V=3kQ2R
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Solution

The correct option is B E=0, V=kQ2R Based on the concept of Gauss's Law, since the electric field inside a conductor is zero, the charge distribution is as shown in figure. We know electric field inside a conductor is zero, thus the magnitude of net electric field, EA=0 at point A as it is inside the material of the conducting shell. Also, net potential, VA=Vs1+Vs2+VQ Vs1→ potential due to outer shell Vs2→ potential due to inner shell VQ→ potential due to point charge ⇒VA=k(−Q)3R/2+k(Q)2R+k(Q)3R/2 ⇒VA=kQ2R

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