A concical tent has slant height of 14 m, and the curved surface area is 308 $m^{2}$ . What is its base area?
154

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Solution

The correct option is A 154
The curved surface area of a cone = $π r l$
where, $r$ is radius and $l$ is slant height.

$\Rightarrow 308 = π r l$
$\Rightarrow \frac{22}{7} \times r \times 14 = 308$
$\Rightarrow r = \frac{308 \times 7}{22 \times 14}$
$\Rightarrow r = 7 m$

Base area
$= π r^{2}$
$= \frac{22}{7} \times 7^{2}$
$= 154 m^{2}$

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. Its slant height is

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. Curved surface area of the cone is:

There is a conical tent whose slant height is 14 $m$ . If the curved surface area of cone is 308 $m^{2}$ ,then find its base area.

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A concical tent has slant height of 14 m, and the curved surface area is 308 m2. What is its base area?154

The correct option is A 154The curved surface area of a cone = πrl where, r is radius and l is slant height. ⇒308=πrl ⇒ 227×r×14=308 ⇒r=308×722×14 ⇒r=7 m Base area =πr2 =227×72 =154 m2

A concical tent has slant height of 14 m, and the curved surface area is 308 $m^{2}$ . What is its base area?
154