A concrete pour of $1080$ cum is planned with a $120$ cum/hr capacity. If the effeciency of the plant is assumed to $75$ %, what will be approximate time taken for completing the pour?

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Solution

The correct option is C $12$
$V o l u m e = 1080 m^{3}$

$c a p a c i t y = 120 m^{3} / h r$

$η = 75$ %

$Q = \frac{V}{t}$

$t = \frac{1080}{120 \times 0.75}$

$t = 12 h r s$

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A concrete pour of 1080 cum is planned with a 120 cum/hr capacity. If the effeciency of the plant is assumed to 75%, what will be approximate time taken for completing the pour?

The correct option is C 12Volume=1080 m3 capacity=120 m3/hr η=75% Q=Vt t=1080120×0.75 t=12 hrs

A concrete pour of $1080$ cum is planned with a $120$ cum/hr capacity. If the effeciency of the plant is assumed to $75$ %, what will be approximate time taken for completing the pour?

The correct option is C $12$
$V o l u m e = 1080 m^{3}$

$c a p a c i t y = 120 m^{3} / h r$

$η = 75$ %

$Q = \frac{V}{t}$

$t = \frac{1080}{120 \times 0.75}$

$t = 12 h r s$