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Standard XII

Physics

Thermal Expansion

A concrete sl...

Question

A concrete slab has a length of 10 m on a winter night when the temperature is $0^{\circ} C$ . Find the length of the slab on a summer day when the temperature is $35^{\circ} C$ . The coefficient of linear expansion of concrete is $1.0 \times 10^{- 5}^{\circ} C^{- 1}$

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Solution

$L_{1} = ? L_{0} = 10 m$

$α = 1 \times 10^{- 5} /^{\circ} C$

$t = 35^{\circ} C$

$L_{1} = L_{0} (1 + α t)$

$= 10 (1 + 10^{- 5} \times 35)$

= 10 + 35 $\times 10^{- 4}$

= 10.0035 m

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A concrete slab has a length of 10 m on a winter night when the temperature is 0∘ C. Find the length of the slab on a summer day when the temperature is 35∘C. The coefficient of linear expansion of concrete is 1.0×10−5 ∘C−1

L1=? L0=10 m α=1×10−5/∘C t=35∘C L1=L0(1+αt) =10(1+10−5×35) = 10 + 35 ×10−4 = 10.0035 m

A concrete slab has a length of 10 m on a winter night when the temperature is $0^{\circ} C$ . Find the length of the slab on a summer day when the temperature is $35^{\circ} C$ . The coefficient of linear expansion of concrete is $1.0 \times 10^{- 5}^{\circ} C^{- 1}$

$L_{1} = ? L_{0} = 10 m$

$α = 1 \times 10^{- 5} /^{\circ} C$

$t = 35^{\circ} C$

$L_{1} = L_{0} (1 + α t)$

$= 10 (1 + 10^{- 5} \times 35)$

= 10 + 35 $\times 10^{- 4}$

= 10.0035 m