Question

A conddenser consist of two parallel plates 0.01m² area and 10^-3m apart in air. If the plates are connected to a battery of emf 100V, calculate the charge on the condenser and the energy stored in it.

Answer 1

ANSWER :-
Given Area=0.01 m^2
distance apart d=10^-3 m
emf =100V
capacitance C= (epsilon zero ×A)/d
=(8.85×10^-12C^2/N.m^2)×0.01/10^-3
= 8.85×10^-11 F

Charge Q=CV =8.85×10^-11×100
=8.85×10^-9 X

Electric field E=V/d
=100/10^-3
=10^5 V/m

Energy stored U=1/2 CV^2
=1/2 × 8.85×10^-11 ×100^2
=1/2×8.85×10^-7
=4.475×10^-7 J