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Question
A condenser is charged to a potential difference of 120V. It's energy is 1×10−5J. If battery is there and the space between plates is filled up with a dielectric medium (εr=5). Its new energy is
A condenser is charged to a potential difference of 120V. It's energy is 1×10−5J. If battery is there and the space between plates is filled up with a dielectric medium (εr=5). Its new energy is
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Solution
The correct option is A 5×10−5J
Given energy = 1×10−5
When battery is connected, V across capacitor will be constant.
When dielectric is filled, C increases by K
∴New energy =12(KC)V 2
=K12CV 2(Given:12CV2=1×10−5 J)
=K(1×10−5) J
=5×(1×10−5) J
=5×10−5 J
Given energy = 1×10−5
When battery is connected, V across capacitor will be constant.
When dielectric is filled, C increases by K
∴New energy =12(KC)V 2
=K12CV 2(Given:12CV2=1×10−5 J)
=K(1×10−5) J
=5×(1×10−5) J
=5×10−5 J
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