Question

A condenser of capacity $1pF$ is connected to an A.C source of $220V$ and $50Hz$ frequency. The current flowing in the circuit will be

• A. $6.9\times {10}^{-8}$A
• B. $6.9$ A
• C. $6.9\times {10}^{-6}$A
• D. zero

Answer 1

Answer: (A)

$6.9\times {10}^{-8}$A

$i_{rms}=\frac{V_{rms}}{1/\omega C}$

$=200\times 2\pi \times 50\times {10}^{-12}$ $(\because \omega =2\pi f)$

$=6.9\times {10}^{-8}$A