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Standard XII

Chemistry

Conductance and Conductivity

A conductance...

Question

A conductance cell when filled with 0.05 M solution of KCl records a resistance of 410.5 ohm at $25^{o} C$ . When filled with $C a C l_{2}$ solution [11 g in 500 mL] it records 990 ohm. If conductivity of 0.05 M KCl is $0.00189 S c m^{- 1}$ ,

The value of molar conductivity of $C a C l_{2}$ solution is:

3.956 S c m^{2} m o l^{- 1}

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5.963 S c m^{2} m o l^{- 1}

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6.953 S c m^{2} m o l^{- 1}

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None of these

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Solution

The correct option is D $3.956 S c m^{2} m o l^{- 1}$
For KCl solution:

$κ = \frac{b}{R}$

Here $κ$ is the conductivity, b is the cell constant and R is the resistance.

$0.00189 S / c m = \frac{b}{410.5 o h m}$

Hence, the cell constant b is $0.776 / c m$

For $C a C l_{2}$ solution:

$κ = \frac{b}{R} = \frac{0.776 / c m}{990 o h m} = 0.000784 S / c m$

The molar concentration is $C = \frac{11 g}{0.5 L \times 111 g / m o l} = 0.198 M$

The molar conductivity of $C a C l_{2}$ solution is $\frac{1000 κ}{C} = \frac{1000 \times 0.000784}{0.198} = 3.956 S c m^{2} / m o l$

Hence, the correct option is $A$

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Similar questions

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A conductance cell when filled with 0.05 M solution of KCl records a resistance of 410.5 ohm at 25oC. When filled with CaCl2 solution [11 g in 500 mL] it records 990 ohm. If conductivity of 0.05 M KCl is 0.00189Scm−1, The value of molar conductivity of CaCl2 solution is: