A conducting bar of length L is free to slide on two parallel conducting rails as shown in figure-Two resistors R1 and R2 are connected across the ends of the rails- There is a uniform magnetic field B pointing into the page- An external agent pulls the bar to the left at a constant speed v- The correct statement about the directions of induced currents I1 and I2 flowing through R1 and R2 respectively is-

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Byju's Answer

Standard XII

Physics

Analysis of Force Equation

A conducting ...

Question

A conducting bar of length $L$ is free to slide on two parallel conducting rails as shown in figure.

Two resistors $R_{1}$ and $R_{2}$ are connected across the ends of the rails. There is a uniform magnetic field $\to B$ pointing into the page. An external agent pulls the bar to the left at a constant speed $v$ . The correct statement about the directions of induced currents $I_{1}$ and $I_{2}$ flowing through $R_{1}$ and $R_{2}$ respectively is:

I_{1}

is in clockwise direction and

I_{2}

is in anticlockwise direction

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Both

I_{1}

and

I_{2}

are in clockwise direction

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I_{1}

is in anticlockwise direction and

I_{2}

is in clockwise direction

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Both

I_{1}

and

I_{2}

are in anticlockwise directon

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Solution

The correct option is A $I_{1}$ is in clockwise direction and $I_{2}$ is in anticlockwise direction

When the bar slides, area of loop 1 decreases and that of loop 2 increases. Magnetic flux decreases in 1 and increases in 2. Therefore, according to Lenz's law, induced emf and current resist this change. As a result, magnetic flux through 1 should increase and through 2 should decrease. So, $I_{1}$ would be clockwise and $I_{2}$ anticlockwise.
Hence option (a) is correct.

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