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Question
A conducting circular loop having a radius of 5.0 cm, is placed perpendicular to a magnetic field of 0.50 T. It is removed from the field in 0.50 s. Find the average emf produced in the loop during this time.
A conducting circular loop having a radius of 5.0 cm, is placed perpendicular to a magnetic field of 0.50 T. It is removed from the field in 0.50 s. Find the average emf produced in the loop during this time.
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Solution
ϕ1=5A=0.5×π(5×10−2)2
=125×10−5
ϕ2=0
E=ϕ1−ϕ2t
=125π×10−55×10−1=25π×10−4
=25×3.14×10−4
=78.5×10−4=7.8×10−3
ϕ1=5A=0.5×π(5×10−2)2
=125×10−5
ϕ2=0
E=ϕ1−ϕ2t
=125π×10−55×10−1=25π×10−4
=25×3.14×10−4
=78.5×10−4=7.8×10−3
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