A conducting circular loop of radius r carries a constant current I it is placed in a uniform magnetic field B such that B is perpendicular to the plane of the loop the magnetic force acting on the loop is

B I R

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2 π (B I R)

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zero

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π (B I R)

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Solution

The correct option is B zero
On a conducting loop net force will be zero due to magnetic field perpendicular to the plane of the loop because for any part of the loop there is a part on opposite direction of current So, force will be opposite in direction on that part. So, net force will be zero.

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[BIT 1992; MP PET 1994; IIT 1983;MP PMT 1999; AMU (Engg.) 2000]

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A conducting circular loop of radius r carries a constant current I it is placed in a uniform magnetic field B such that B is perpendicular to the plane of the loop the magnetic force acting on the loop is

The correct option is B zeroOn a conducting loop net force will be zero due to magnetic field perpendicular to the plane of the loop because for any part of the loop there is a part on opposite direction of current So, force will be opposite in direction on that part. So, net force will be zero.

The correct option is B zero
On a conducting loop net force will be zero due to magnetic field perpendicular to the plane of the loop because for any part of the loop there is a part on opposite direction of current So, force will be opposite in direction on that part. So, net force will be zero.