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Question

A conducting ring of mass 2 kg and radius 0.5m is placed on a smooth horizontal plane. The ring carries a current i=4A. A horizontal magnetic field B=10T is switched on at t=0 as shown in figure. The initial angular acceleration is :

23871_5e0e475ebf4346a8be7c5b98a62aedfc.png

A
40π rad/s2
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B
20π rad/s2
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C
5π rad/s2
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D
15π rad/s2
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Solution

The correct option is B 20π rad/s2
Torque on the ring is,
τ=M×B
τ=MBSinθ
=iπr2BSin90
=4×π×0.25×10×1
=10π Nm
τ=Iα
10π=Mr2α
α=10π2×0.25=20π rad/s2

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