Question

A conducting rod $AB$ moves parallel to the x-axis in a uniform magnetic field pointing in the positive z direction. The end $A$ of the rod gets positively charged. explain.

Answer 1

Let $l$ be the length of rod AB.

Applying right hand rule,emf induced in direction of B to A.

i.e, A is higher potential induced emf $e=vBl$

Electric field $\overrightarrow{E}=\frac{e}{l}=vB$ from A to B.