Question

A conducting rod of $1\text{m}$ length is rotating with a frequency of $50\text{rev/s}$ inside the uniform magnetic field of $6.28\text{mT}$. The magnetic field is perpendicular to the plane of rotation.

Instead of rotating, if the rod moves with a speed of $v=6.28\text{m/s}$ in the plane perpendicular to the magnetic field, then the emf induced between the ends of the rod will be -

$v$ is perpendicular to the length of the rod.

​​​​​​​$[$1 Mark$]$

• A. $1\text{V}$
• B. $0.02\text{V}$
• C. $0.04\text{V}$
• D. $6.28\text{V}$

Answer 1

The correct option is C $0.04\text{V}$

If the rod is moving in a magnetic field perpendicular to the plane of motion, motional emf will be induced.

Motional EMF,

$\epsilon =Blv=(6.28\times {10}^{-3})\times 1\times 6.28$

$\Rightarrow \epsilon =0.04\text{V}$