Question

A conducting rod of length 2l is rotating with constant angular speed $\omega$ about its perpendicular bisector. A uniform magnetic field exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is

• A. $B\omega l^2$
  
• B. $\frac{1}{2}B\omega l^2$
  
• C. $\frac{1}{8}B\omega l^2$
  
• D. Zero

Answer 1

The correct option is D Zero

Potential difference between
O and A is $V_0-V_A=\frac{1}{2}B{l}^2\omega$
O and B is $V_0-V_B=\frac{1}{2}B{l}^2\omega$
so $V_A-V_B=0$