A conducting rod of length $l$ is moving in a transverse magnetic field of strength $B$ with velocity $v$ . The resistance of the rod is $R$ . The current in the rod is

\frac{B l v}{R}

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B l v

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Z e r o

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\frac{B^{2} v^{2} l^{2}}{R}

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Solution

The correct option is A $\frac{B l v}{R}$
Les consider, $l =$ length of a conducting rod
$B =$ transverse magnetic field
$v =$ velocity
$R =$ resistance
The motional emf induced in the conducting rod is given by
$E = B l v$
The current in the rod is
$I = \frac{E}{R}$
$I = \frac{B l v}{R}$
The correct option is A.

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A conducting rod of length l is moving in a transverse magnetic field of strength B with velocity v. The resistance of the rod is R. The current in the rod is

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