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Question

A conducting rod of mass m and length l is placed in the east-west direction on a frictionless horizontal table. The horizontal component of earth's magnetic field is B from south to north. If charge q is suddenly passed through the conductor, then the instantaneous velocity acquired by the rod is

A
2Blqm
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B
Blq2m
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C
Blqm
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D
(2Blq)2m2
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Solution

The correct option is C Blqm
A conducting rod of mass=m
Length=lMagnetic field=B
Charge=q
Now the required formula of the velocity using
12mv2=qE12mv2=qBl[F=Bl]v=2qBlm
Since, Impulse= Change in linear momentum
F.dt=(ilB)dtmVidt=qmv2=Blqv2=Blqm

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