A conducting rod PQ is moving parallel to X-axis in a uniform magnetic filed directed in positive Y-direction. The end P of the rod will become
A
negative
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B
positive
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C
neutral
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D
sometimes negative
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Solution
The correct option is B positive Force of positive charges in rod = q→v×→B As v is along x axis and B is along y axis the force will be along the z axis. Therefore the positive charges will move towards the end P and it will become positive charged.