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Question

A conducting rod PQ of length L = 1.0 m is moving with uniform speed v = 2.0 ms1 in a uniform magnetic field B = 4.0 T directed into the paper. A capacitor of capacity C = 10 μF is connected as shown in the figure. Then after a long time charge on plates of capacitor is


A

qA = + 80 μ C and qB = - 80 μC

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B

qA = - 80 μ C and qB = +80 μC

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C

qA = qB = 0

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D

Charge stored in the capacitor can’t be determined

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Solution

The correct option is A

qA = + 80 μ C and qB = - 80 μC


EMF=Bvl

And q=cV


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