CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A conducting sphere A of radius a, with charge Q is placed concentrically inside a conducting shell B of radius b.B is earthed, C is the common centre of A and B. If P is the point between shells A and B at distance r from center C then Match the proper entries from column- 2 to column- 1 using the codes given below the columns, (use a=1 m,b=3 m,r=2 m and K=14πε0)


Column-I Column-II
(p) Electric field at point P is (1) 2KQ3
(q) Electric potential at point P is (2) zero
(r) Electric potential difference between A and B is (3) KQ4
(s) Electric field outside the shell B at distance
5 m from centre C is
(4) KQ6

A
p-4; q-2; r-1; s-3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
p-1; q-2; r-4; s-3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
p-2; q-3; r-4; s-1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
p-3; q-4; r-1; s-2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D p-3; q-4; r-1; s-2

Field at P will only be due to A as electric field inside the conducting sphere B will be zero.
EP =kQ(2)2=kQ4
Potential at P=Vdue to A +Vdue to B =kQ2kQ3
Electric field outside B is due to 'A's Induced charge on B+A s charge.
Eoutside=kQ52kQ52= 0

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electric Potential as a Property of Space
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon