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Question

A conducting sphere of radius 10 cm is charged to 10 μ C. Another uncharged sphere of radius 20 cm is allowed to touch it for some time. After that if the spheres are separated then surface density of charges, on the spheres will be in the ratio of:


A
1:3
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B
3:1
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C
2:1
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D
1:1
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Solution

The correct option is C 2:1
After redistribution, new charges on sphere are
Q1=(1010+20)×10=103 μC
and Q2=(2010+20)×10=203 μC
Ratio of charge densities

σ1σ2=Q1Q2×r22r21=(103203)×(2010)2=21

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