CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A conducting sphere of radius 10 cm is charged to 10 μ C. Another uncharged sphere of radius 20 cm is allowed to touch it for some time. After that if the spheres are separated then surface density of charges, on the spheres will be in the ratio of:


A
1:3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2:1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2:1
After redistribution, new charges on sphere are
Q1=(1010+20)×10=103 μC
and Q2=(2010+20)×10=203 μC
Ratio of charge densities

σ1σ2=Q1Q2×r22r21=(103203)×(2010)2=21

flag
Suggest Corrections
thumbs-up
40
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Idea of Capacitance
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon