A conducting spherical shell of radius 1 m is charged upto potential of 10 volt. Another conducting spherical shell of radius 2 m is charged upto potential of 10 volt. Now smaller sphere is placed inside the bigger sphere by insulating handle and connect them by a conducting wire

No flow to charge between the spheres as same potential

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Potential of outer sphere will become 15 volt

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Potential of inner sphere will become 6 volt

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Both (2) & (3)

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Solution

The correct option is C Potential of outer sphere will become 15 volt
Given
potential of radius $1 m$ sphere is $10 V$
potential of radius $2 m$ sphere is $10 V$
We know that
$V = \frac{K Q}{R}$
Putting all value in above equation
$10 = \frac{K Q}{1} K Q = 10$
potential at outer sphere is sum of both sphere potential When both sphere connected by wire.
Potential of another sphere $= \frac{K Q}{R} = \frac{10}{2} = 5 V$
$S u m = 10 + 5 = 15 V$

Correct option is B

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