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Question

A conducting square frame of side a and a long straight wire carrying current I are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity V. The emf induced in the frame will be proportional to
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A
1(2x+a)2
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B
1(2xa)(2x+a)
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C
1x2
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D
1(2xa)2
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Solution

The correct option is A 1(2xa)(2x+a)
Induced emf ε=B1avB2av=μ0I2π(xa2avμ0I2π(x+a2))av=μ0Iav2π(1xa21x+a2)=μ0Iav2πa(2xa)(2x+a)
B1(2xa)(2x+a)


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