A conducting square loop is placed in a magnetic field B with its plane perpendicular to the field. Some how the sides of the loop start shrinking at a constant rate α. The induced emf in the loop at an instant when its side is a, is :
A
2aαB
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B
a2αB
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C
2a2αB
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D
aαB
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Solution
The correct option is A2aαB At time t Side of square l=li−dt S=l2=(li−αt)2 At given time l=li−αt=a ϕ=BS=B(li−αt)2 e=∣∣∣dϕdt∣∣∣=2Bα(li−αt) But (li−αt)=a ∴e=2aαB