The correct option is C 10e Ω
For conducting wire,
Ti=0∘ C; Tf=273∘C
⇒ΔT=273∘C
Resistance is given by
R=R0(1+αΔT)
The formula is only valid when temperature change is very small. However, here term αΔT is significant thus it will contradict the truncation of series- expansion.
From basic definition of α,
dR=RαdT
⇒dRR=αdT
Integrating both side
R2∫R1dRR=αT2∫T1dT=α[T2−T1]
⇒[lnR]R210=α(273−0)=1273×273=1
⇒lnR210=1⇒R210=e
∴R2=10e Ω
Why this question?The formula for obtaining resistance asa function of temperature R=R0(1+αΔT) must not be applied for large value of ΔT.