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Question

A conducting wire has a resistance of 10 Ω at 0C and its coefficient of thermal resistance is α=1273/C. The resistance of wire at a temperature 273C will be
(lne=1)

A
5 Ω
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B
10e Ω
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C
10e Ω
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D
20 Ω
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Solution

The correct option is C 10e Ω
For conducting wire,
Ti=0 C; Tf=273C

ΔT=273C

Resistance is given by

R=R0(1+αΔT)

The formula is only valid when temperature change is very small. However, here term αΔT is significant thus it will contradict the truncation of series- expansion.

From basic definition of α,

dR=RαdT

dRR=αdT

Integrating both side

R2R1dRR=αT2T1dT=α[T2T1]

[lnR]R210=α(2730)=1273×273=1

lnR210=1R210=e

R2=10e Ω

Why this question?The formula for obtaining resistance asa function of temperature R=R0(1+αΔT) must not be applied for large value of ΔT.

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