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Standard X

Physics

Faraday's Law

A conducting ...

Question

A conducting wire in the form of circular loop of radius $\sqrt{\frac{2}{π}}$ m is places normal to a uniform magnetic field of induction 2T. If the magnetic induction is uniformly reduced to T in 2s, the induced e.m.f in the loop is ____________.

4

volt

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2

volt

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1

volt

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0.4

volt

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Solution

The correct option is D $1$ volt
$\frac{d B}{d t} = \frac{1 - 2}{2} = - \frac{1}{2}$

Induced EMF $= n A \frac{d B}{d t} = 1 \times π {(\sqrt{\frac{2}{π}})}^{2} \times (- \frac{1}{2}) = 1 V o l t$

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A conducting wire in the form of circular loop of radius √2πm is places normal to a uniform magnetic field of induction 2T. If the magnetic induction is uniformly reduced to T in 2s, the induced e.m.f in the loop is ____________.

The correct option is D 1voltdBdt=1−22=−12Induced EMF =nAdBdt=1×π(√2π)2×(−12)=1Volt

A conducting wire in the form of circular loop of radius $\sqrt{\frac{2}{π}}$ m is places normal to a uniform magnetic field of induction 2T. If the magnetic induction is uniformly reduced to T in 2s, the induced e.m.f in the loop is ____________.

The correct option is D $1$ volt
$\frac{d B}{d t} = \frac{1 - 2}{2} = - \frac{1}{2}$

Induced EMF $= n A \frac{d B}{d t} = 1 \times π {(\sqrt{\frac{2}{π}})}^{2} \times (- \frac{1}{2}) = 1 V o l t$