A conducting wire is sliding in a uniform magnetic field- As the wire moves- emf is induced- and according to Lenz-s law- motion is retarded- The work done by the magnetic field is given by W magnetic- Then-A- W magnetic is positive since electrons are being pumped for current flow-B- W magnetic is negative- since motion is being retarded-C- None of the above-D- W magnetic is zero- became magnetic force is always - to velocity-

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Force on a Current Element

A conducting ...

Question

A conducting wire is sliding in a uniform magnetic field. As the wire moves, emf is induced, and according to Lenz's law, motion is retarded. The work done by the magnetic field is given by $W_{m a g n e t i c}$ . Then,

W_{m a g n e t i c}

is negative, since motion is being retarded.

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W_{m a g n e t i c}

is positive since electrons are being pumped for current flow.

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W_{m a g n e t i c}

is zero, became magnetic force is always

⊥

to velocity.

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None of the above.

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Solution

The correct option is C $W_{m a g n e t i c}$ is zero, became magnetic force is always $⊥$ to velocity.
Magnetic force is always $⊥$ to velocity of a particle; hence, $P o w e r = \to l . \to v = 0$ or $W_{m a g n e t i c} = 0$ .

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A conducting wire is sliding in a uniform magnetic field. As the wire moves, emf is induced, and according to Lenz's law, motion is retarded. The work done by the magnetic field is given by $W_{m a g n e t i c}$ . Then,

The correct option is C $W_{m a g n e t i c}$ is zero, became magnetic force is always $⊥$ to velocity.
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