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Question

A conductivity cell filled with 0.01M KCl gives at 25°C the resistance of 604 ohms. The conductivity of KCI at 25°C is
0.00141 2 cm1.
The same cell filled with 40.001M AgNO3 gives resistance of 6529 ohms. Calculate the molar conductivity of 0.001M AgNO3 solution at 25°C ?

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Solution

σconc = cellconstR
0.00141×604=6529×x
x is specific conducters
x = 0.000130
molar conductivity = 0.0001300.001
0.13 answer

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