Question

A conductivity cell filled with $0.1MKCl$ gives at ${25}^{o}C$ a resistance of $85.5$ ohms. The conductivity of same cell filled with $0.005MHCl$ gives a resistance of $529$ ohms. What is the molar conductivity of $HCl$ solution at ${25}^{o}C$?

Answer 1

$0.1MKCl$ $R=85.5$ohm
$k=0.01286$
$f=\frac{1}{k}=77.76$
$R=f\frac{l}{A}$
$\frac{l}{A}=\frac{R}{f}=\frac{85.5}{77.76}$
$=1.04c{m}^{-1}$
$R=5290$ohm
$f=\frac{R}{l/A}=\frac{529}{1.09}=481.11$
$k=\frac{1}{f}=2.07\times {10}^{-3}$
$m=\frac{k\times 1000}{M}=\frac{2.07\times {10}^{-3}\times 1000}{0.005}$
$=415.70$
$\approx 416$