.A conductor AB of length l carrying a current i is placed perpendicular to a long straight conductor XY carrying a current l, as shown. the force on AB will act
A
along x to y
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B
along y to x
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C
to the right
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D
to the left
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Solution
The correct option is A along x to y →F=i(→l×→B) Here, direction of →B due to XY wire is into the paper at AB So, →l×→B is towards X to Y. So, force is along X to Y direction.