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Question

A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 wb/m2, as shown in fig. If all the four sides are of 1m length each, then the induced emf between points A and D is



A
1.41 volt
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B
0.71 volt ​
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C
None of the above
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Solution

The correct option is A 1.41 volt
There is no induced emf in the part AB and CD because they are moving along their length while emf induced between B and C i.e. between A and D can be calculated


Induced emf between B and C = Induced emf between A and B=Bv(2l)=1×1×1×2=1.41 volt


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