A conductor carries a current of 0.2 A. How many electrons will flow in 30 seconds if the charge on one electron is 1.6×10−19 C.
3.75×1019
It is given that current I=0.2 A, time t=30 s and charge on one electron is e=1.6×10−19 C.
Let the number of electrons be n.
We know I=Qt and Q=n×e where e is the charge on one electron.
So, I=n×et
On substituting the values, 0.2=n×1.6×10−1930
⇒ n=3.75×1019
Therefore, 3.75×1019 electrons will flow in 30 seconds.