A conductor carries a current of $3 m A$ . The number of electrons passing through it in one minute is about:

10^{18}

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10^{20}

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10^{23}

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10^{25}

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Solution

The correct option is A $10^{18}$
Current, $I = 3 m A = 3 \times 10^{- 3} A$

Hence, charge passing per minute, $Q = I t = 3 \times 10^{- 3} \times 60 = 0.18 C$
And charge on one electron $= e = 1.6 \times 10^{- 19} C$

Hence, number of electron $= N = \frac{Q}{e}$

$⟹ N = \frac{0.18}{1.6 \times 10^{- 19}}$

$⟹ N \approx 10^{18}$

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A conductor carries a current of 3 mA. The number of electrons passing through it in one minute is about:

The correct option is A 1018Current, I=3 mA=3×10−3AHence, charge passing per minute, Q=It=3×10−3×60=0.18 CAnd charge on one electron=e=1.6×10−19 CHence, number of electron=N=Qe⟹N=0.181.6×10−19⟹N≈1018

A conductor carries a current of $3 m A$ . The number of electrons passing through it in one minute is about: