A conductor carries a current of 3 mA. The number of electrons passing through it in 1 minute is about

10^{18}

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10^{20}

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10^{23}

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10^{25}

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Solution

The correct option is A $10^{18}$
Given : $e = 1.6 \times 10^{- 19}$ C $I = 0.003$ A $t = 60$ s
Using $I = \frac{n e}{t}$
$∴$ Number of electrons $n = \frac{I t}{e} = \frac{0.003 \times 60}{1.6 \times 10^{- 19}} = 1.12 \times 10^{18}$ electrons

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A conductor carries a current of 3 mA. The number of electrons passing through it in 1 minute is about

The correct option is A 1018Given : e=1.6×10−19 C I=0.003 A t=60 sUsing I=net∴ Number of electrons n=Ite=0.003×601.6×10−19=1.12×1018 electrons

The correct option is A $10^{18}$
Given : $e = 1.6 \times 10^{- 19}$ C $I = 0.003$ A $t = 60$ s
Using $I = \frac{n e}{t}$
$∴$ Number of electrons $n = \frac{I t}{e} = \frac{0.003 \times 60}{1.6 \times 10^{- 19}} = 1.12 \times 10^{18}$ electrons