A conductor carries a current of $50 μ A$ . If the area of cross-section of the conductor is $50 {m m}^{2}$ , then value of the current density in $A m^{- 2}$ is

0.5

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1

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10^{- 1}

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3 / 10

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Solution

The correct option is B $1$
current density $i = \frac{P}{A} = \frac{50 \times 10^{- 6}}{60 \times 10^{- 6}} m^{2} = 1 A m^{- 2}$

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