A conductor in the form of a right angle ABC with AB = 3cm and BC = 4 cm carries a current of 10 A. There is a uniform magnetic field of 5T perpendicular to the plane of the conductor. The force on the conductor will be
A
1.5 N
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B
2.0 N
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C
2.5 N
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D
3.5 N
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Solution
The correct option is C 2.5 N According to the question figure can be drawn as shown below. Force on the conductor ABC = Force on the conductor AC =5×10×(5×10−2) =2.5N