A conductor in the form of a right angle ABC with AB=3cm and BC=4cm carries a current of 10A. There is a uniform magnetic field of 5T perpendicular to the plane of the conductor. The force on the conductor will be
A
1.5N
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B
2.0N
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C
2.5N
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D
3.5N
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Solution
The correct option is C2.5N F=Bil=5×10×5×10−2N=2.5N