A conductor is located at x - 0-4 m- y - 0 and 0 - z -2 m- which carries a current of 10 A in - direction along the length of conductor- B-2-5-x- T is the magnetic field density- The torque generated about the z-axis will be

We know, nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; F=I(L×B) nbsp; nbsp; nbsp; nbsp; ...

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Standard XII

Mathematics

Implication

A conductor i...

Question

A conductor is located at x = 0.4 m, y = 0 and 0 < z <2 m, which carries a current of 10 A in $_{z}$ direction along the length of conductor, $\to B = 2.5_{x} T$ is the magnetic field density. The torque generated about the z-axis will be

20_{y}

N-m

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20_{x}

N-m

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10_{y}

N-m

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20_{z}

N-m

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Solution

The correct option is D $20_{z}$ N-m
We know,
$\to F = I (\to L \times \to B)$
= $10 (2_{z} \times 2.5_{x}) = 50_{y} N$

$\to T = \to r \times \to F = (0.4_{x}) \times (50_{y})$

= $20_{z}$ N-m

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A conductor is located at x = 0.4 m, y = 0 and 0 < z <2 m, which carries a current of 10 A in ^az direction along the length of conductor, →B=2.5^axT is the magnetic field density. The torque generated about the z-axis will be

The correct option is D 20^az N-mWe know, →F=I(→L×→B) = 10(2^az×2.5^ax)=50^ay N →T=→r×→F=(0.4^ax)×(50^ay) = 20^az N-m

A conductor is located at x = 0.4 m, y = 0 and 0 < z <2 m, which carries a current of 10 A in $_{z}$ direction along the length of conductor, $\to B = 2.5_{x} T$ is the magnetic field density. The torque generated about the z-axis will be

The correct option is D $20_{z}$ N-m
We know,
$\to F = I (\to L \times \to B)$
= $10 (2_{z} \times 2.5_{x}) = 50_{y} N$

$\to T = \to r \times \to F = (0.4_{x}) \times (50_{y})$

= $20_{z}$ N-m