Question

A conductor of length $1m$ and carrying current of $1A$ is placed at an angle ${45}^{\circ }$ to the magnetic field of 1 oersted. The force acting on conductor is

• A. $\frac{{10}^{-4}}{\sqrt{2}}N$
• B. $\frac{{10}^{-4}}{\sqrt{3}}N$
• C. $\frac{{10}^{-2}}{\sqrt{3}}N$
• D. $\frac{{10}^{-2}}{\sqrt{2}}N$

Answer 1

The correct option is A $\frac{{10}^{-4}}{\sqrt{2}}N$

It is given that,

Length, $l=1m$

Current, $I=1A$

Magnetic field, $B=1oersted={10}^{-4}Kg/A{s}^2$

Magnetic force,

$F=I(L\times B)$

$F=1(1\times {10}^{-4}\sin 45)$

$F=\frac{{10}^{-4}}{\sqrt{2}}$