You visited us 9 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Two Parallel Currents

A conductor o...

Question

A conductor of length 2 m carrying current 2 A is held parallel to an infinitely long conductor carrying current of 12 A at a distance of 100 mm, the force j on a small conductor is:

8.6 x

10^{- 5} N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.6 x

10^{- 5} N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7.6 x

10^{- 5} N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9.6 x

10^{- 5} N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is A 9.6 x $10^{- 5} N$
Here, $I_{1}$ = 2 A, $I_{2}$ = 12 A, r = 100 mm = 0.1 m, l = 2 m
Now total force on length l of small conductor

$F = \frac{μ_{0} 2 I_{1} I_{2} l}{4 π r} = \frac{10^{- 7} \times 2 \times 2 \times 12 \times 2}{0.1}$

$F = 9.60 \times 10^{- 5} N$

Suggest Corrections

Similar questions

Along an infinitely long conductor carrying a current of 8 A we keep another conductor of length 5 m carrying a current of 3 A. Both the conductors are 10 cm apart. Find the force on small conductor.

Q. Figure shows a square loop.

20 cm

on each side in the x-y plane with its centre at the origin. The loop carries a current of

7 A

.
Above it at

y = 0, z = 12 cm

is an infinitely long wire parallel to the x-axis carrying a current of

10 A

. The net force on the loop is ———

\times 10^{- 5} N

Q. A long straight conductor carrying a current of 2 A is in parallel to another conductor of length 5 cm and carrying a current 3 A. They are separated by a distance of 10 cm B due to first conductor at second conductor is

Q. Figure below shows two infinitely long and thin current carrying conductors

X

and

Y

kept in vacuum, parallel to each other, at a distance

^{'} a

Define ampere, in terms of force between two current carrying conductors

A straight,long wire carries a current of 20 A.Another wire carrying equal current is placed parallel to it.If the force acting on a length of 10 cm of the second wire is $2.0 \times 10^{- 5} N$ ,what is the separation between them ?

Join BYJU'S Learning Program

A conductor of length 2 m carrying current 2 A is held parallel to an infinitely long conductor carrying current of 12 A at a distance of 100 mm, the force j on a small conductor is:

The correct option is A 9.6 x 10−5NHere,I1 = 2 A,I2 = 12 A, r = 100 mm = 0.1 m, l = 2 mNow total force on length l of small conductorF=μ02I1I2l4πr=10−7×2×2×12×20.1F=9.60×10−5N

The correct option is A 9.6 x $10^{- 5} N$
Here, $I_{1}$ = 2 A, $I_{2}$ = 12 A, r = 100 mm = 0.1 m, l = 2 m
Now total force on length l of small conductor

$F = \frac{μ_{0} 2 I_{1} I_{2} l}{4 π r} = \frac{10^{- 7} \times 2 \times 2 \times 12 \times 2}{0.1}$

$F = 9.60 \times 10^{- 5} N$