A conductor of length l is placed perpendicular to a horizontal uniform magnetic field B. Suddenly a certain amount of charge is passed through it, when it is found to jump to a height h. The amount of charge that passes through the conductor is

\frac{m \sqrt{g h}}{B l}

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\frac{m \sqrt{g h}}{2 B l}

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\frac{m \sqrt{2 g h}}{B l}

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Solution

The correct option is C $\frac{m \sqrt{2 g h}}{B l}$
Impulse = Change in momentum

$\int F d t = m v - 0$
$\int I l B d t = m v - 0$
$l B \int I d t = m v$

$l B \int d q = m v$

$d q = \frac{m v}{l B} = \frac{m \sqrt{2 g h}}{l B}$

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A conductor of length l is placed perpendicular to a horizontal uniform magnetic field B. Suddenly a certain amount of charge is passed through it, when it is found to jump to a height h. The amount of charge that passes through the conductor is

The correct option is C m√2ghBlImpulse = Change in momentum ∫F dt=mv−0 ∫I lB dt=mv−0 lB∫I dt=mv lB∫dq=mv dq=mvlB=m√2ghlB

The correct option is C $\frac{m \sqrt{2 g h}}{B l}$
Impulse = Change in momentum

$\int F d t = m v - 0$
$\int I l B d t = m v - 0$
$l B \int I d t = m v$

$l B \int d q = m v$

$d q = \frac{m v}{l B} = \frac{m \sqrt{2 g h}}{l B}$