A conductor of length $x$ and diameter $x$ has a resistance $x$ . The resistivity of the material is:

π x^{3} / 4

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π x^{2}

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π x^{2} / 4

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π x / 2

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Solution

The correct option is C $π x^{2} / 4$
$R = \frac{ρ L}{A}$
$x = \frac{ρ x}{\frac{π x^{2}}{4}}$
$ρ = \frac{π x^{2}}{4}$

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